document.write( "Question 134463: I HOPE U CAN HELP ME WITH THIS....SOLVE THE EQUATION AND INEQUALITIES. WRITE THE SOLUTION TO THE INEQUALITIES IN INTERVAL NOTATION. THANK U.\r
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Algebra.Com's Answer #98356 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
A) \r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%283-p%29-4=2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%283-p%29=6\" Add 4 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%283-p%29=3\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3-p=-3\" or \"3-p=3\" Set the expression \"3-p\" equal to the original value 3 and it's opposite -3\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"3-p=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-p=-3-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-p=-6\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"p=%28-6%29%2F%28-1%29\" Divide both sides by -1 to isolate p\r
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\n" ); document.write( "\n" ); document.write( "\"p=6\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"3-p=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-p=3-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-p=0\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"p=%280%29%2F%28-1%29\" Divide both sides by -1 to isolate p\r
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\n" ); document.write( "\n" ); document.write( "\"p=0\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"2%2Aabs%283-p%29-4=2\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"p=6\" or \"p=0\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=2%2Aabs%283-x%29-4\" and \"y=2\" (just set each side equal to y and graph), we get\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28500%2C500%2C-2%2C8%2C-10%2C10%2C2%2Aabs%283-x%29-4%2C2%29\" Graph of \"y=2%2Aabs%283-x%29-4\" (red) and \"y=2\"(green)\r
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\n" ); document.write( "\n" ); document.write( "and we can see the two graphs intersect at \"x=6\" and \"x=0\". So this verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%283-p%29-4%3C2\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%283-p%29%3C6\" Add 4 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%283-p%29%3C3\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29%3C+a\", then \"x+%3E+-a\" and \"x+%3C+a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3-p+%3E+-3\" and \"3-p+%3C+3\" Break up the absolute value inequality using the given rule\r
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\n" ); document.write( "\n" ); document.write( "\"-3+%3C+3-p+%3C+3\" Combine the two inequalities to get a compound inequality\r
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\n" ); document.write( "\n" ); document.write( "\"-6+%3C+-p+%3C+0\" Subtract 3 from all sides\r
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\n" ); document.write( "\n" ); document.write( "\"6+%3E+p+%3E+0\" Multiply all sides by -1 to isolate p. This will flip the inequality signs\r
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\n" ); document.write( "\n" ); document.write( "\"0%3Cp%3C6\" Rearrange the inequality\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
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\n" ); document.write( "\n" ); document.write( "which looks like this in interval notation\r
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\n" ); document.write( "\n" ); document.write( "if you wanted to graph the solution set, you would get\r
\n" ); document.write( "\n" ); document.write( " Graph of the solution set in blue and the excluded values represented by open circles
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