document.write( "Question 134454: solve the linear equation by substitution\r
\n" ); document.write( "\n" ); document.write( "x-3y=5
\n" ); document.write( "-2x+6y=-10
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Algebra.Com's Answer #98351 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Start with the given system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x-3y=5%2C-2x%2B6y=-10%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "So let's isolate y in the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"x-3y=5\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"-3y=5-x\" Subtract \"x\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3y=-x%2B5\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-x%2B5%29%2F%28-3%29\" Divide both sides by \"-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-1%29%2F%28-3%29%29x%2B%285%29%2F%28-3%29\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F3%29x-5%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Since \"y=%281%2F3%29x-5%2F3\", we can now replace each \"y\" in the second equation with \"%281%2F3%29x-5%2F3\" to solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B6highlight%28%28%281%2F3%29x-5%2F3%29%29=-10\" Plug in \"y=%281%2F3%29x-5%2F3\" into the first equation. In other words, replace each \"y\" with \"%281%2F3%29x-5%2F3\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B%286%29%281%2F3%29x%2B%286%29%28-5%2F3%29=-10\" Distribute \"6\" to \"%281%2F3%29x-5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B%286%2F3%29x-30%2F3=-10\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B2x-10=-10\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"-30=-30\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"0=-30%2B30\"Add 30 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "Since this equation is always true for any x value, this means x can equal any number. So there are an infinite number of solutions.
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