document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134406>Question 134406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you begin to solve the equation 3x+x(x-1)=0.  I have worked and worked on this problem.  I have an answer but when put back in to equation to check. It does not work.  My answer is  1 + square root of 11 / 2 , 1 - square root of 11/2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98316 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would you begin to solve the equation 3x+x(x-1)=0<BR>\n" );
document.write( "Perform the indicated operations:<BR>\n" );
document.write( "3x + x^2 - x = 0<BR>\n" );
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document.write( "x^2 + 3x - x = 0<BR>\n" );
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document.write( "x^2 + 2x = 0<BR>\n" );
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document.write( "Factor out x:<BR>\n" );
document.write( "x(x + 2) = 0<BR>\n" );
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document.write( "Giving you two solutions<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = -2<BR>\n" );
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document.write( "Substituting either solution, confirms the equation </SPAN>\n" );
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