document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2275>Question 2275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle length is 5cm more than its width.if the preimeter is 40cm find the length and width          \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #983 by </B><A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><B>gsmani_iyer(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gsmani_iyer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( "  perimeter(p) = 2l + 2b = 2(l+b)\r<BR>\n" );
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document.write( "  Let the width be = x cm<BR>\n" );
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document.write( "  So length = x + 5 cms.<BR>\n" );
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document.write( "  By applying the above formula, <BR>\n" );
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document.write( "  40 cms = 2(x+x+5)<BR>\n" );
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document.write( "  20 cms = x+x+5 = 2x+5<BR>\n" );
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document.write( "  2x = 20-5 = 15<BR>\n" );
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document.write( "  x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2F2 ALIGN=MIDDLE  ALT=\"15%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 7.5 cms.<BR>\n" );
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document.write( "  So width = 7.5 cms.;  length = 7.5+5 = 12.5 cms.  Ans.<BR>\n" );
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