document.write( "Question 134374: A boat travels 60km upstream in 5 hours. The boat travles the same distance downstream in 3 hours. Whatis the rate of the boat in still water? what is the rate of the current?\r
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\n" ); document.write( "\n" ); document.write( "okay I really tried, but i just can't get it...\r
\n" ); document.write( "\n" ); document.write( "s=d/T
\n" ); document.write( "s=60/5=12
\n" ); document.write( "60/3
\n" ); document.write( "12-10=2
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Algebra.Com's Answer #98291 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A boat travels 60km upstream in 5 hours. The boat travels the same distance downstream in 3 hours. What is the rate of the boat in still water? what is the rate of the current?
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\n" ); document.write( "Let s = speed of the boat in still water
\n" ); document.write( "Let c = speed of the current
\n" ); document.write( "Then
\n" ); document.write( "(s+c) = speed downstream
\n" ); document.write( "and
\n" ); document.write( "(s-c) = speed upstream
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\n" ); document.write( "We can write two distance equations, one upstream, on downstream
\n" ); document.write( "Dist = time * speed
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\n" ); document.write( "5(s-c) = 60
\n" ); document.write( "3(s+c) = 60
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\n" ); document.write( "We can simplify both equations, divide the 1st one by 5, and the 2nd one by 3
\n" ); document.write( "s - c = 12
\n" ); document.write( "s + c = 20
\n" ); document.write( "------------adding equations eliminates c, find s
\n" ); document.write( "2s + 0 = 32
\n" ); document.write( "s = 32/2
\n" ); document.write( "s = 16 km/hr is speed in still water
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\n" ); document.write( "Find c using the 2nd simplified equation
\n" ); document.write( "s + c = 20
\n" ); document.write( "16 +c = 20
\n" ); document.write( "c = 20 - 16
\n" ); document.write( "c = 4 km/hr is the speed of the current
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\n" ); document.write( "Check solution in one of the original equations
\n" ); document.write( "5(16 - 4) = 60; confirms our solutions
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