document.write( "Question 134344: four years ago, katie was twice as old as anne was then. in 6 years, anne will be the same age that katie is now. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #98251 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
four years ago, katie was twice as old as anne was then. in 6 years, anne will be the same age that katie is now. how old is each now?
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Four years ago DATA:
\n" ); document.write( "Let Ann's age be x ; Then Katie's age was 2x.
\n" ); document.write( "-----------------------------
\n" ); document.write( "6 years from now Ann's age will be \"x+10\"
\n" ); document.write( "Katies's age NOW is \"2x+4\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "x+10 = 2x+4
\n" ); document.write( "x = 6
\n" ); document.write( "------------
\n" ); document.write( "Katie's age NOW is 2x+4 = 2*6+4 16 yrs old
\n" ); document.write( "Ann's age NOW is x+4 = 6+4 = 10 yrs old
\n" ); document.write( "==========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );