document.write( "Question 134344: four years ago, katie was twice as old as anne was then. in 6 years, anne will be the same age that katie is now. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #98251 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! four years ago, katie was twice as old as anne was then. in 6 years, anne will be the same age that katie is now. how old is each now? \n" ); document.write( "------------------------------------- \n" ); document.write( "Four years ago DATA: \n" ); document.write( "Let Ann's age be x ; Then Katie's age was 2x. \n" ); document.write( "----------------------------- \n" ); document.write( "6 years from now Ann's age will be \"x+10\" \n" ); document.write( "Katies's age NOW is \"2x+4\" \n" ); document.write( "----------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "x+10 = 2x+4 \n" ); document.write( "x = 6 \n" ); document.write( "------------ \n" ); document.write( "Katie's age NOW is 2x+4 = 2*6+4 16 yrs old \n" ); document.write( "Ann's age NOW is x+4 = 6+4 = 10 yrs old \n" ); document.write( "========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |