document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134324>Question 134324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a 75-degree sector rotates around the center of a circle in 75-degree movements, howmnay sector movements will be needed for the sector to land in its original position? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98244 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in 5 steps, the sector rotates 375°; which puts it 15° out of sync\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "each additional 5 steps rotates the sector 375° and puts it another 15° out of sync\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "after 5 rotations (25 steps), the sector is 75° out of sync; which means one step back puts it in sync\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so, 24 steps </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );