document.write( "Question 134316: Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 yr? After 2 yrs? \n" ); document.write( "
Algebra.Com's Answer #98235 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"%281yr%29\"
\n" ); document.write( "\"+A+=+2000+%2B+2000%28.06%2A1%29\"
\n" ); document.write( "\"A+=+2000+%2B+120\"
\n" ); document.write( "\"A+=+2120\"..........the balance after \"1\" year \r
\n" ); document.write( "\n" ); document.write( "(2yr)
\n" ); document.write( "\"A+=+2000+%2B+2000%28.06%2A2%29\"
\n" ); document.write( "\"A+=+2000+%2B+2000%28.12%29\"
\n" ); document.write( "\"A+=+2000+%2B+240\"
\n" ); document.write( "\"A+=++2240\".........the balance after \"2\" years
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