document.write( "Question 20356: Help would be greatly appreciated!!\r
\n" ); document.write( "\n" ); document.write( "Solve for X\r
\n" ); document.write( "\n" ); document.write( " X: 64= 2^3x
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Algebra.Com's Answer #9823 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
i assume you mean \"64+=+2%5E%283x%29\" rather than \"64+=+%282%5E3%29x\"\r
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\n" ); document.write( "\n" ); document.write( "If so, we have the variable (x) as a \"power\". To remove this, take logs. Since the base is 2, use this as your log base.\r
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\n" ); document.write( "\n" ); document.write( "So, \"log64+=+log%282%5E%283x%29%29\" where the logs are base2.\r
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\n" ); document.write( "\n" ); document.write( "--> 6 = 3x
\n" ); document.write( "--> 2 = x\r
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\n" ); document.write( "\n" ); document.write( "done :-)\r
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\n" ); document.write( "\n" ); document.write( "jon.
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