document.write( "Question 134172: find the z score that separates the middle 63% of the distrubution from the area in the tails of the standard normal distribution
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Algebra.Com's Answer #98227 by stanbon(75887)\"\" \"About 
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find the z score that seperates the middle 63% of the distrubution from the area in the tails of the standard normal distribution
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\n" ); document.write( "Middle 63% means 31.5% to the right and 31.5% to the left of the mean.
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\n" ); document.write( "The z scores are +/- 0.8965___
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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