document.write( "Question 134172: find the z score that separates the middle 63% of the distrubution from the area in the tails of the standard normal distribution
\n" );
document.write( " The z scores are___ \n" );
document.write( "
Algebra.Com's Answer #98227 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the z score that seperates the middle 63% of the distrubution from the area in the tails of the standard normal distribution \n" ); document.write( "------------ \n" ); document.write( "Middle 63% means 31.5% to the right and 31.5% to the left of the mean. \n" ); document.write( "Use you z-chart to find \n" ); document.write( "The z scores are +/- 0.8965___ \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |