document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20355>Question 20355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am cannnot solve this problem no matter how hard I try. Any sort of help would be greatly appreciated!!\r<BR>\n" );
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document.write( "Solve log2 8+ log2 32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9821 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok, logs to the base 2.... log 8 means what is the power of 2 needed to get 8? Answer is 3...2^3 is 2x2x2 which is 8.\r<BR>\n" );
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document.write( "Similarly, what is the power of 2 needed to get 32? Answer is 5 --> 2x2x2x2x2 which is 32.\r<BR>\n" );
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document.write( "so log8 + log32 becomes 3 + 5 which is 8. That is the answer.\r<BR>\n" );
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document.write( "Jon. </SPAN>\n" );
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