document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134230>Question 134230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the exact length of the side of a square which has a diagonal of 100 ft.\r<BR>\n" );
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document.write( "The hypotenuse of a right triangle measures 100 inches, and one leg measures 50  inches. find the measure of the other leg.<BR>\n" );
document.write( "a) give its length in simplified radical form.<BR>\n" );
document.write( "b) Round the answer to the nearest thousandth.\r<BR>\n" );
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document.write( "I dont like word problems could you help me?<BR>\n" );
document.write( "Thank U :) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98163 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> These use the Pythagorean theorem which states that if you have two legs of a right triangle, say a and b, and a hypotenuse, c, then:<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "In the first problem you need to remember that the sides of a square have the exact same length and that the interior angles of a square all measure 90 degrees.  This means that the diagonal forms a right triangle with two of the sides.  so to find the side lengths you can use the formula above where c = 100 feet.<br>\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2 where b and c are the same so this really becomes<BR>\n" );
document.write( "2a^2 = c^2 <br>\r<BR>\n" );
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document.write( "now we just need to plug in numbers and solve.<br>\r<BR>\n" );
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document.write( "2a^2 = 100<BR>\n" );
document.write( "a^2 = 50<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2850%29 ALIGN=MIDDLE  ALT=\"sqrt%2850%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+sqrt%282%29 ALIGN=MIDDLE  ALT=\"5+sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "Now for the second problem.  We know that one of the legs is 50 inches, lets call this a.  our c value is 100 inches so now all we need to do is solve for b.<br>\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "50^2 + b^2 = 100^2<BR>\n" );
document.write( "2500 + b^2 = 10000<BR>\n" );
document.write( "b^2 = 7500<BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%287500%29 ALIGN=MIDDLE  ALT=\"sqrt%287500%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10sqrt%2875%29 ALIGN=MIDDLE  ALT=\"10sqrt%2875%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50sqrt%283%29 ALIGN=MIDDLE  ALT=\"50sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "thats your answer for part a.<br>\r<BR>\n" );
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document.write( "part b is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50sqrt%283%29 ALIGN=MIDDLE  ALT=\"50sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 86.602 </SPAN>\n" );
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