document.write( "Question 133919: Hello the section im working on is on solving rational equations. I dont understand this one im working on.
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document.write( "Here it is\r
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document.write( "x/x-1 + x = 4x-3/x-1\r
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document.write( "Thanks for the help \n" );
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Algebra.Com's Answer #98161 by algebrapro18(249)![]() ![]() ![]() You can put this solution on YOUR website! Well first you need to get a common denominator. Since 2/3 of the fractions have a denominator of x-1 that will be your common denominator. So multiply everything by x-1 and the denominator cancles off leaving you with. \r \n" ); document.write( "\n" ); document.write( "x+x(x-1)=4x-3 \r \n" ); document.write( "\n" ); document.write( "now just solve: \n" ); document.write( "x+x(x-1)=4x-3 --> Distribute the x \n" ); document.write( "x + x^2 - x = 4x - 3 --> Collect like terms on left hand side \n" ); document.write( "x^2 - 4x + 3 = 0 --> Factor \n" ); document.write( "(x-1)(x-3) = 0 --> Set each factor equal to zero and solve \n" ); document.write( "x = 1 and x = 3 \r \n" ); document.write( "\n" ); document.write( "Now lets check our solutions \r \n" ); document.write( "\n" ); document.write( "x/x-1 + x = 4x-3/x-1 \r \n" ); document.write( "\n" ); document.write( "when x = 1 you get \r \n" ); document.write( "\n" ); document.write( "1/1-1 + 1 = 4-3/1-1 well since you can't divide by zero we know that x = 1 is a extraneous answer. \r \n" ); document.write( "\n" ); document.write( "when x = 3 you get \r \n" ); document.write( "\n" ); document.write( "3/3-1 + 3 = 4(3)-3/3-1 \n" ); document.write( "3/2 + 3 = 12-3/2 \n" ); document.write( "3/2 + 3 = 9/2 \n" ); document.write( "9/2 = 9/2 \r \n" ); document.write( "\n" ); document.write( "that one checks out. \n" ); document.write( " |