document.write( "Question 134154: I still need help:
\n" ); document.write( "please help me solve the following synthetic division i am struggling with
\n" ); document.write( "Use synthetic division and the remainder theroem to find the indicated function value.\r
\n" ); document.write( "\n" ); document.write( "f(x)=6x to the 4th power +11x³+6x²-6x+53; f(4)
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Algebra.Com's Answer #98139 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find f(4), we can use synthetic division with the test zero of 4\r
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\n" ); document.write( "\n" ); document.write( "First set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.\n" ); document.write( "\n" ); document.write( "
4|6116-653
|
\r
\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 6)\r
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4|6116-653
|
6
\r
\n" ); document.write( "\n" ); document.write( " Multiply 4 by 6 and place the product (which is 24) right underneath the second coefficient (which is 11)\r
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4|6116-653
|24
6
\r
\n" ); document.write( "\n" ); document.write( " Add 24 and 11 to get 35. Place the sum right underneath 24.\r
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4|6116-653
|24
635
\r
\n" ); document.write( "\n" ); document.write( " Multiply 4 by 35 and place the product (which is 140) right underneath the third coefficient (which is 6)\r
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4|6116-653
|24140
635
\r
\n" ); document.write( "\n" ); document.write( " Add 140 and 6 to get 146. Place the sum right underneath 140.\r
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4|6116-653
|24140
635146
\r
\n" ); document.write( "\n" ); document.write( " Multiply 4 by 146 and place the product (which is 584) right underneath the fourth coefficient (which is -6)\r
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4|6116-653
|24140584
635146
\r
\n" ); document.write( "\n" ); document.write( " Add 584 and -6 to get 578. Place the sum right underneath 584.\r
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4|6116-653
|24140584
635146578
\r
\n" ); document.write( "\n" ); document.write( " Multiply 4 by 578 and place the product (which is 2312) right underneath the fifth coefficient (which is 53)\r
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4|6116-653
|241405842312
635146578
\r
\n" ); document.write( "\n" ); document.write( " Add 2312 and 53 to get 2365. Place the sum right underneath 2312.\r
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4|6116-653
|241405842312
6351465782365
\r
\n" ); document.write( "\n" ); document.write( "Since the last column adds to 2365, we have a remainder of 2365. \r
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\n" ); document.write( "\n" ); document.write( "So \"f%284%29=2365\"
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