document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134161>Question 134161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with the following homework question, I believe the obvious answer is 600 but I'm not sure. P(x)=-0.002x²+1.2x-300 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98136 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(X)=-.002X^2+1.2X-300<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "X=(-1.2+-SQRT{1.2^2-4*-.002*-300])/2*-.002<BR>\n" );
document.write( "X=(-1.2+-SQRT[1.44-2.4])/-.004<BR>\n" );
document.write( "X=)-1.2+-SQRT-.96)/-.004<BR>\n" );
document.write( "X=(-1.2+-.98i)/-.004<BR>\n" );
document.write( "X=(-1.2/-.004+-.98i/-.004<BR>\n" );
document.write( "X=300+-245i ANSWERS. </SPAN>\n" );
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