document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134181>Question 134181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem.\r<BR>\n" );
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document.write( "Two angles are supplementary. The measure of one is twice the measure of the other. What is the measure of the larger angle?\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98133 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=180<BR>\n" );
document.write( "X=2Y NOW REPLACE X BY 2Y & SOLVE FOR Y<BR>\n" );
document.write( "2Y+Y=180<BR>\n" );
document.write( "3Y=180<BR>\n" );
document.write( "Y=180/3<BR>\n" );
document.write( "Y=60 ANSWER FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "X=2*60=120 ANSWER FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60=120=180<BR>\n" );
document.write( "180=180\r<BR>\n" );
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document.write( " </SPAN>\n" );
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