document.write( "Question 134143: this question is so easy but yet i just can't figure it out. It's driving me crazy. I just need the fomula, i think. okay so here it is.
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document.write( "One-third of a number is 5 less than half of the same number. What is the number? \n" );
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Algebra.Com's Answer #98107 by nycsharkman(136)![]() ![]() ![]() You can put this solution on YOUR website! One-third of a number is 5 less than half of the same number. What is the number?\r \n" ); document.write( "\n" ); document.write( "Let x = the missing number\r \n" ); document.write( "\n" ); document.write( "1/3(x) = (1/2)(x) - 5\r \n" ); document.write( "\n" ); document.write( "We now solve for x.\r \n" ); document.write( "\n" ); document.write( "(1/3)(x) can be written as simply x/3.\r \n" ); document.write( "\n" ); document.write( "(1/2)(x) can be written as simply x/2.\r \n" ); document.write( "\n" ); document.write( "We now have a fractional equation:\r \n" ); document.write( "\n" ); document.write( "x/3 = x/2 - 5....Much easier to work with, right?\r \n" ); document.write( "\n" ); document.write( "To remove the fractions, we multiply both sides of the equation by the LCD, which is 6.\r \n" ); document.write( "\n" ); document.write( "x/3 times 6 = 2x\r \n" ); document.write( "\n" ); document.write( "x/2 times 6 = 3x\r \n" ); document.write( "\n" ); document.write( "-5 times 6 = -30\r \n" ); document.write( "\n" ); document.write( "We now have a linear equation:\r \n" ); document.write( "\n" ); document.write( "2x = 3x - 30\r \n" ); document.write( "\n" ); document.write( "Subtract 3x from 2x.\r \n" ); document.write( "\n" ); document.write( "2x - 3x = -30\r \n" ); document.write( "\n" ); document.write( "-x = -30\r \n" ); document.write( "\n" ); document.write( "Divide both sides by -1 to find our missing number.\r \n" ); document.write( "\n" ); document.write( "x = -30/-1\r \n" ); document.write( "\n" ); document.write( "x = 30\r \n" ); document.write( "\n" ); document.write( "So, what is the missing number? The missing number is 30.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |