document.write( "Question 134139: ten times the complement of an angle exceeds 3 times the supplement of the same angle by 318. What is the angle? \n" ); document.write( "
Algebra.Com's Answer #98104 by solver91311(24713)\"\" \"About 
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Apparently you are using degree measurements, so the complement of an angle that measures \"alpha\" degrees is \"90-alpha\" and the supplement is \"180-alpha\"\r
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\n" ); document.write( "\n" ); document.write( "Ten times the complement (\"10%2890-alpha%29\")
\n" ); document.write( "Three times the supplement (\"3%28180-alpha%29\")
\n" ); document.write( "Exceeds by 318: +318, so:\r
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\n" ); document.write( "\n" ); document.write( "\"10%2890-alpha%29=3%28180-alpha%29%2B318\" (ten times the complement is the bigger number so you have to add the 318 to the smaller number to make them equal)\r
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\n" ); document.write( "\n" ); document.write( "\"900-10alpha=540-3alpha%2B318\"\r
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\n" ); document.write( "\n" ); document.write( "\"-10alpha%2B3alpha=540%2B318-900\"\r
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\n" ); document.write( "\n" ); document.write( "\"-7alpha=-42\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"90-6=84\"
\n" ); document.write( "\"10%2A84=840\"\r
\n" ); document.write( "\n" ); document.write( "\"180-6=174\"
\n" ); document.write( "\"3%2A174=522\"\r
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\n" ); document.write( "\n" ); document.write( "\"840-522=318\"
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