document.write( "Question 134056: Graph (x+3) (x-2)^2=0 (use maxs, mins, x and y intercepts) \n" ); document.write( "
Algebra.Com's Answer #98085 by solver91311(24713) You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Zeros, or x-intercepts at -3, 2, and 2 (we should have an extrema at 2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expand: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Extreme points where f'(x) = 0, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f'(x) = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We know that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And we have an extreme point at \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f\"(x)= \n" ); document.write( "f\"(2)= \n" ); document.write( "f\"(-4/3)= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The y-intercept is found by evaluating f(0): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using this information, we can make a rough sketch of the graph:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |