document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134095>Question 134095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the indicated composite for the pair of functions.<BR>\n" );
document.write( "18) (g &#8728; f)(x): f(x) =  <BR>\n" );
document.write( "x - 3<BR>\n" );
document.write( "6<BR>\n" );
document.write( ", g(x) = 6x + 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98064 by </B><A HREF=/tutors/aboutme.mpl?userid=Madgamer107><B>Madgamer107(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Madgamer107><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (g o f)(x) simply means g(f(x)). Since you know f(x), you can plug that into g(x) to find the composition.\r<BR>\n" );
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document.write( "f(x) = x - 36 (hard to tell from your text; i assume this is what you meant)<BR>\n" );
document.write( "g(x) = 6x + 3<BR>\n" );
document.write( "g(f(x)) = 6(x - 36) + 3<BR>\n" );
document.write( "g(f(x)) = 6x - 216 + 3<BR>\n" );
document.write( "g(f(x)) = 6x - 213\r<BR>\n" );
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document.write( "(g o f)(x) = 6x - 213 </SPAN>\n" );
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