document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=134086>Question 134086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne is now seven times as old as joan.In six years ann will be five times as old as joan.find the age of each one.<BR>\n" );
document.write( "Let a=Anne's age j=Joan's age<BR>\n" );
document.write( " a = 7j now.------------(1)<BR>\n" );
document.write( "In 6 yrs, a+6 =5(j+6)---(2)\r<BR>\n" );
document.write( "\n" );
document.write( "(2)-(1): 6= 5(j+6)-6j==><BR>\n" );
document.write( "6=5j+30-7j =30-2j==><BR>\n" );
document.write( "j=24/2=12. Substitute j=12 in (1)  to get a=7*12=84.<BR>\n" );
document.write( "a= Anne's age=84 and j=joan's age =12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #98048 by </B><A HREF=/tutors/aboutme.mpl?userid=Ganesha><B>Ganesha(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ganesha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=98048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a=Anne's age j=Joan's age<BR>\n" );
document.write( " a = 7j now.------------(1)<BR>\n" );
document.write( "In 6 yrs, a+6 =5(j+6)---(2)\r<BR>\n" );
document.write( "\n" );
document.write( "(2)-(1): 6= 5(j+6)-6j==><BR>\n" );
document.write( "6=5j+30-7j =30-2j==><BR>\n" );
document.write( "j=24/2=12. Substitute j=12 in (1)  to get a=7*12=84.<BR>\n" );
document.write( "a= Anne's age=84 and j=joan's age =12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );