document.write( "Question 134075: solve the equation by completing the square
\n" ); document.write( "x^2+6x+2=0
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Algebra.Com's Answer #98047 by solver91311(24713)\"\" \"About 
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\"x%5E2%2B6x%2B2=0\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1: Move the constant term to the right hand side of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Divide the coefficient on the 1st degree term by 2\r
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\n" ); document.write( "\n" ); document.write( "\"6%2F2=3\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Square the result of Step 2:\r
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\n" ); document.write( "\n" ); document.write( "\"3%5E2=9\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Add the result of Step 3 to both sides of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x%2B9=-2%2B9\"
\n" ); document.write( "\"x%5E2%2B6x%2B9=7\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5: The left side of the equation is now a perfect square, so factor it:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%5E2=7\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6: Take the square root of both sides, remembering to consider both the positive and negative roots:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3=sqrt%287%29\" or \"x%2B3=-sqrt%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 7: Isolate x:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3%2Bsqrt%287%29\" or \"x=-3-sqrt%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 8: Check your answers\r
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