document.write( "Question 133975: How many ways can you make a change for a dollar using no pennies and at most 1 nickel? Please help I am confused. Thanks \n" ); document.write( "
Algebra.Com's Answer #98017 by solver91311(24713)\"\" \"About 
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You don't say whether $1.00 and/or $0.50 coins are available. Let's exclude the $1.00 coin because that is trivial. So you have four different coins available, half-dollar, quarter, dime, and at most one nickel.\r
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\n" ); document.write( "\n" ); document.write( "You could use two half dollars\r
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\n" ); document.write( "\n" ); document.write( "You could use one half dollar and two quarters\r
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\n" ); document.write( "\n" ); document.write( "One half dollar, one quarter, two dimes and one nickel\r
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\n" ); document.write( "\n" ); document.write( "One half dollar, no quarters, and five dimes\r
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\n" ); document.write( "\n" ); document.write( "(You can't have one half dollar, no quarters, four dimes and two nickels because that violates the 'one nickel' rule)\r
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\n" ); document.write( "\n" ); document.write( "No half dollars, three quarters, two dimes, one nickel\r
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\n" ); document.write( "\n" ); document.write( "No half dollars, two quarters, five dimes\r
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\n" ); document.write( "\n" ); document.write( "No half dollars, one quarter, seven dimes, one nickel\r
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\n" ); document.write( "\n" ); document.write( "Ten dimes\r
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\n" ); document.write( "\n" ); document.write( "All together, 8 ways. If you don't have half dollar coins, then only count the ways that don't use half dollars, total 4.
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