document.write( "Question 134007: Angela needs 20qts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each should she use? \n" ); document.write( "

Algebra.Com's Answer #97998 by checkley71(8403) $\"\"$ $\"About$

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X+.4(20-X)=.5*20
\n" ); document.write( "X+8-.4X=10
\n" ); document.write( ".6X=10-8
\n" ); document.write( ".6X=2
\n" ); document.write( "X=2/.6
\n" ); document.write( "X=3 1/3 OR 10/3 QTS OF PURE ANTIFREEZE IS NEEDED.
\n" ); document.write( "PROOF
\n" ); document.write( "10/3+.4(20-10/3)=10
\n" ); document.write( "10/3+.4[(60-10)/3]=10
\n" ); document.write( "10/3+.4(50/3)=10
\n" ); document.write( "10/3+20/3=10
\n" ); document.write( "30/3=10
\n" ); document.write( "10=10 \n" ); document.write( "

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