document.write( "Question 133857: peter started driving at 4:50 and is driving at an average speed of 30 mi/hr. dina is driving at an average of 40 mi/ hr. and she started driving at 5:20 if they both started driving from the same point, after how many hours would the meet?
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Algebra.Com's Answer #97987 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! peter started driving at 4:50 and is driving at an average speed of 30 mi/hr. dina is driving at an average of 40 mi/ hr. and she started driving at 5:20 if they both started driving from the same point, after how many hours would the meet? \n" ); document.write( ": \n" ); document.write( "From the information given we know that d's travel time was a half hour less than p's travel time \n" ); document.write( ": \n" ); document.write( "Let t = p's travel time \n" ); document.write( "then \n" ); document.write( "(t-.5) = d's travel time \n" ); document.write( ": \n" ); document.write( "We d catches up with p, the will have traveled the same distance \n" ); document.write( "write a distance equation from this fact: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "d's distance = p's dist \n" ); document.write( "40(t-.5) = 30t \n" ); document.write( "40t - 20 = 30t \n" ); document.write( "40t - 30t = 20 \n" ); document.write( "t = 20/10 \n" ); document.write( "t = 2 hrs is p's travel time; \n" ); document.write( ": \n" ); document.write( "d catches up with p at 6:50 \n" ); document.write( ": \n" ); document.write( "Check solution by confirming that the distances are equal \n" ); document.write( "30(2) = 60 mi \n" ); document.write( "40(1.5) = 60 also \n" ); document.write( " |