document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133983>Question 133983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my equation  has a trianglewith the hypotenuse at 10 centimeters the adjacent side is 3x centimeters and my opposite is x centimeters. I know that the pythagoreum theroreum is A squared + B squared = C squared and I got to the point where X centimeters squared + 3X centimeters squared = 100 centimeters could you help me please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97953 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+3x^2=100<BR>\n" );
document.write( "4x^2=100<BR>\n" );
document.write( "x^2=100/4<BR>\n" );
document.write( "x^2=25<BR>\n" );
document.write( "x=sqrt25<BR>\n" );
document.write( "x=5 answer,<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "25+3*25=100<BR>\n" );
document.write( "25+75=100<BR>\n" );
document.write( "100=100<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );