document.write( "Question 133910: The ages of Ann and Bill now add up to 91. Ann is three times as old as Bill was at the time when Ann was twice as old as Bill is now. How old are Ann and Bill now? \n" ); document.write( "
Algebra.Com's Answer #97941 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! Let,\r \n" ); document.write( "\n" ); document.write( "x= Bill's age \n" ); document.write( "Now, being Ann as 3 times a sold as Bill at the time when Ann was twice as old as Bill; \n" ); document.write( "3* (2x) = Ann's age \n" ); document.write( "Therefore, \n" ); document.write( "Bill's age + Ann's age = 91 \n" ); document.write( "x + 3 (2x) =91 \n" ); document.write( "x+ 6x = 91 \n" ); document.write( "x= 91/7 \n" ); document.write( "x = 13 , Bill's age now\r \n" ); document.write( "\n" ); document.write( "For Ann's age, 3 (2*13) = 78 yrs old \n" ); document.write( "This just make sense because there was a time when Ann's age was twice as that of Bill, 2*13 = 26. And 3 times this age equals 78, plus 13 (Bill's age now) sum up to 91. Perfect! \n" ); document.write( " |