document.write( "Question 133926: President Abraham Lincoln was 6 feet 4 inches tall. An artist wants to make a larger-than-life statue of Lincoln using a scale of 1 inch = 2 feet. How tall will the statue be?\r
\n" ); document.write( "\n" ); document.write( "a.12 feet 8 inches
\n" ); document.write( "b.25 feet 4 inches
\n" ); document.write( "c.76 feet
\n" ); document.write( "d.152 feet\r
\n" ); document.write( "\n" ); document.write( "it states that the right answer is d but i'm not sure how to set it up in a porportion to get that answer.
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Algebra.Com's Answer #97935 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
In this case, you really don't need to 'set up' a proportion. If the scale is 1 inch = 2 feet, meaning that every 1 inch of Mr. Lincoln's real height would be represented by 2 feet, or 24 inches in the statue, then all you really need to do is multiply 6 ft 4 inches by 24. Conveniently, 6 ft 4 in is 6 and 1/3 feet, or \"19%2F3\" ft. \"%2819%2F3%29%2A24=19%2A8=152\" Larger than life? I should say so. Lay it down on a football field with the feet at one of the goal lines, and the head would just cross the mid-field stripe. \n" ); document.write( "
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