document.write( "Question 133896: An auto mechanic has 300mL of batter acid solution that is 60% acid. He must add water to this solution to dilute it so that it is only 45% acid. How much water should he add? \n" ); document.write( "

Algebra.Com's Answer #97923 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=amount of water that needs to be added\r
\n" ); document.write( "\n" ); document.write( "Now we know that the pure acid in the water (0) plus the pure acid in the 60% solution (0.60*300) has to equal the amount of pure acid in the final mixture (0.45(300+x))\r
\n" ); document.write( "\n" ); document.write( "So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.60*300=0.45(300+x) simplify
\n" ); document.write( "180=135+0.45x subtract 135 from each side
\n" ); document.write( "180-135=0.45x
\n" ); document.write( "0.45x=45 divide both sides by 0.45\r
\n" ); document.write( "\n" ); document.write( "x=100ml------------------amount of water that needs to be added\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "0.60*300=0.45*400
\n" ); document.write( "180=180\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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