document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133839>Question 133839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7/ 3-5i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97921 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "7/(3-5i)  First, we'll multiply the numerator and denominator by the conjugate of 3-5i which is 3+5i.  This will get rid of the radical in the denominator.\r<BR>\n" );
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document.write( "(7(3+5i))/((3-5i)(3+5i)) =<BR>\n" );
document.write( "(7(3+5i))/(9-25(i^2)) but i^2 is -1, so\r<BR>\n" );
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document.write( "(7(3+5i))/(9+25)=<BR>\n" );
document.write( "7(3+5i)/34\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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