document.write( "Question 133893: this question comes from a teacher-made worksheet
\n" ); document.write( "Solve 2 ways: \"log+%28%282-5x%29%2F%282x%2B16%29%29+=0\" ; x = -2\r
\n" ); document.write( "\n" ); document.write( "I have solved it one way, but I don't know the other:
\n" ); document.write( "\"log+%28%282-5x%29%2F%282x%2B16%29%29+=0\"
\n" ); document.write( "\"log%28%282-5x%29%29+-+log%28%282x%2B16%29%29+=+0\"
\n" ); document.write( "\"log%28%282-5x%29%29+=+log%28%282x%2B16%29%29\"
\n" ); document.write( "\"2-5x+=+2x%2B16\"
\n" ); document.write( "\"-7x+=+14\"
\n" ); document.write( "\"x+=+-2\"
\n" ); document.write( "

Algebra.Com's Answer #97912 by Ganesha(13)\"\" \"About 
You can put this solution on YOUR website!
Log([2-5x]/[2x+16]) = 0
\n" ); document.write( "If log a = k, then a =e^k\r
\n" ); document.write( "\n" ); document.write( "Hence (2-5x)/(2x+16) =e^0 =1\r
\n" ); document.write( "\n" ); document.write( "2-5x = 2x+16 ==>\r
\n" ); document.write( "\n" ); document.write( "-5x-2x = 16-2 = 14==>\r
\n" ); document.write( "\n" ); document.write( "-7x=14==>\r
\n" ); document.write( "\n" ); document.write( "x = 14/2 = -2
\n" ); document.write( "
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