document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133865>Question 133865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is 8-x =2x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97903 by </B><A HREF=/tutors/aboutme.mpl?userid=snwbrdfrk><B>snwbrdfrk(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=snwbrdfrk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok this is easy. the first thing you need to do is get your x's by itself so since the equation 8-x=2x-1 you need 2x and x together.<BR>\n" );
document.write( "the first thing to do is either subtract both sides by 8 or add both sides by one. im going to add both sides by one. it should look like this.<BR>\n" );
document.write( "1+8-x=2x<BR>\n" );
document.write( "7-x=2x<BR>\n" );
document.write( "now what we need to do is add both sides by x since it is negative. its just like we did with 1.<BR>\n" );
document.write( "7=x+2x<BR>\n" );
document.write( "7=3x<BR>\n" );
document.write( "7/3=x<BR>\n" );
document.write( "or 2.34\r<BR>\n" );
document.write( "\n" );
document.write( "there you go<BR>\n" );
document.write( "i hope i helped </SPAN>\n" );
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