document.write( "Question 133852: The sum of the digits of a two-digit number is 13. If the digits are reversed, the new number is 4 less than twice the original number. Find the original number.\r
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document.write( "I an very confused with this problem.\r
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document.write( "It's be greatly appreciated if I could get help! \n" );
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Algebra.Com's Answer #97894 by solver91311(24713) You can put this solution on YOUR website! 10s digit: x \n" ); document.write( "1s digit: y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The original number: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reversing the digits makes a new number: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Twice the original number is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we know that the sum of the digits is 13, we can say \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the 10s digit of the original number (and the ones digit of the new number) is 4. Therefore the ones digit of the original number must be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "Number is: 49 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |