document.write( "Question 133836: y=2x-6
\n" ); document.write( "Graph the equation and identify the y intercept.\r
\n" ); document.write( "\n" ); document.write( "Can someone help me with this please, I do not understand this at all.I do not understand how I come with number for the X what do i do to get that number??
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Algebra.Com's Answer #97892 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Graph the equation and identify the y-intercept:
\n" ); document.write( "\"y+=+2x-6\" First, to graph this linear equation, you need only to assign values to the indepedent variable, that's x, then calculate the corresponding value of the dependent variable, that's y. Since a straight line requires only two points to define it, that's all you need to find. So, assign some convenient value to x, like zero, (x=0) for example, then find the corresponding value of y.
\n" ); document.write( "\"y+=+2%280%29-6\"
\n" ); document.write( "\"y+=+-6\" So here's your first point: (0, -6)
\n" ); document.write( "Now for the second point, let x = 3.
\n" ); document.write( "\"y+=+2%283%29-6\"
\n" ); document.write( "\"y+=+0\" ...and here's your second point: (3, 0)
\n" ); document.write( "Now. on your coordinate graph paper with the x- and y-axes drawn in, you mark these two points then draw a straight line through them to get your graph, easy, right?
\n" ); document.write( "As for the y-intercept, this is x- and y-location on your graph where the line you have drawn intersects the y-axis.
\n" ); document.write( "It happens that the x-value will be zero, so the y-value is -6 (0, -6) which happens to be one of the two points you got for the graph.
\n" ); document.write( "Here's a picture of the graph:
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-8%2C5%2C2x-6%29\"
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