document.write( "Question 133783: Hello I am having some trouble with a few word problems. I just can't seem to get them.
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document.write( "The length of a rectangle is 4 times as long as it is wide. If the perimeter is 60 meters, find the dimensions of the length and width. \r
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document.write( "The length is 4 times as long as it is wide... Isn't half of the perimeter what I need to multiply by? I'm very confused. It seems simple but I dont know how to set up the problem the right way. 4x+30?\r
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document.write( "Thank you for your time,
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document.write( "Mrs. Gibson \n" );
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Algebra.Com's Answer #97882 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "MRS. GIBSON, THE PERIMETER OF A RECTANGLE IS 2*LENGTH+2*WIDTH\r \n" ); document.write( "\n" ); document.write( "IF WE LET W=WIDTH \n" ); document.write( "THEN 4W (WE ARE TOLD)=LENGTH \n" ); document.write( "SO, PERIMETER=2*W+2*4W=60m\r \n" ); document.write( "\n" ); document.write( "2W+8W=60\r \n" ); document.write( "\n" ); document.write( "10W=60 \n" ); document.write( "W=6 M---------WIDTH \n" ); document.write( "LENGTH=4W=4*6=24 M\r \n" ); document.write( "\n" ); document.write( "ck \n" ); document.write( "2*6+2*24=60 \n" ); document.write( "12+48=60 \n" ); document.write( "60=60\r \n" ); document.write( "\n" ); document.write( "HOPE THIS HELPS---PTAYLOR \n" ); document.write( " \n" ); document.write( " |