document.write( "Question 133736: HELP please...
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document.write( "Solve using the addition principle.
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document.write( "2x + 5 < x+4 (the arrow is underlined) The solution set is {x|x< ?}\r
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document.write( "Solve using the multiplication principle.
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document.write( "5x>-4 (the arrow is underlined)\r
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document.write( "Translate to an inequality
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document.write( "A number is at least 14
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document.write( "(the answer is ? ? ?)
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document.write( "Use x as a variable \n" );
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Algebra.Com's Answer #97854 by dolly(163)![]() ![]() ![]() You can put this solution on YOUR website! 2x + 5 < = x + 4 \n" ); document.write( "Adding -x to both sides, \n" ); document.write( "==> 2x + 5 - x < = x + 4 - x \n" ); document.write( "==> x + 5 < = 4 \n" ); document.write( "Adding -5 to both sides, \n" ); document.write( "==> x + 5 - 5 < = 4 - 5 \n" ); document.write( "==> x < = -1 \n" ); document.write( "Thus solution set is {x | x < or = - 1}\r \n" ); document.write( "\n" ); document.write( "(ii) 5x > = -4 \n" ); document.write( "Multiplying both sides by 1/5 \n" ); document.write( "==> (1/5) 5x > = - 4(1/5) \n" ); document.write( "==> 5x/5 > = -4/5 \n" ); document.write( "==> x > = -4/5 \n" ); document.write( "Thus solution set is {x | x > or = - 4/5}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(iii)A number is at least 14 \n" ); document.write( "Let x be the number \n" ); document.write( "Then x > = 14\r \n" ); document.write( "\n" ); document.write( "good luck!!! \n" ); document.write( " \n" ); document.write( " |