document.write( "Question 133737: am trying to figure out a problem, that I cannot, for the life of me seem to answer by showing my work. The answer is supposed to be either -1&-2 or 3&4.\r
\n" ); document.write( "\n" ); document.write( "Here is my question.\r
\n" ); document.write( "\n" ); document.write( "The sum of two consecutive integers is 5 less than their product. Find the integers.\r
\n" ); document.write( "\n" ); document.write( "I found them, but I cannot show HOW I got them. ??\r
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Algebra.Com's Answer #97853 by dolly(163)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "I'll help you out.\r
\n" ); document.write( "\n" ); document.write( "Let the consecutive integers be x, x+1.\r
\n" ); document.write( "\n" ); document.write( "Then by the given data,\r
\n" ); document.write( "\n" ); document.write( "x(x+1) = x + x+1 + 5
\n" ); document.write( "==> x^2 + x = 2x + 6
\n" ); document.write( "==> x^2 + x - 2x - 6 = 0
\n" ); document.write( "==> x^2 - x - 6 = 0
\n" ); document.write( "==> x^2 - 3x + 2x - 6 = 0
\n" ); document.write( "==> x(x - 3) + 2(x - 3) = 0
\n" ); document.write( "==> (x - 3) (x + 2) = 0
\n" ); document.write( "==> x - 3 = 0 or x + 2 = 0
\n" ); document.write( "==> x = 3 or x = -2
\n" ); document.write( "If x = 3, then other number is 4 [as (x+1)]
\n" ); document.write( "So the integers are 3 and 4.\r
\n" ); document.write( "\n" ); document.write( "If x = -2, then the other number is = -1 [ as x+1]
\n" ); document.write( "So the integers are -2 and -1.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps.\r
\n" ); document.write( "\n" ); document.write( "good luck!!!\r
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