document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133725>Question 133725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I usually do really well with most of these mixture problems, but this one has me stuck:\r<BR>\n" );
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document.write( "A forester mixes gasoline and oil to make 2 gallons of a mixture for his two-cycle chainsaw engine.  This mixture is 32 parts gasoline and 1 part two-cycle oil.  How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil? Question 72, page 108, College Algebra, 7th Edition, Larson/Hostetler\r<BR>\n" );
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document.write( "Thank you!<BR>\n" );
document.write( "Jasmine </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97844 by </B><A HREF=/tutors/aboutme.mpl?userid=kev82><B>kev82(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kev82><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Currently you have 2/33 gallons of oil (2 gallons of which 1/33 is oil). You wish to achieve the ratio 40:1 so you need 40 times more gasonline = 40*2/33 = 80/33. Currently you have 64/33 gallons of gasoline in the mixture so you need to add 80/33 - 64/33 = 16/33.  </SPAN>\n" );
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