document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20245>Question 20245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I calculate;<BR>\n" );
document.write( "I have 2 wells, well A produces water with 18 ppb of a mineral<BR>\n" );
document.write( "Well B produces water with 3 ppb of the same mineral.<BR>\n" );
document.write( "How many gallons per minute should I blend of well A water with how many gallons per minute of well B water to produce a combined water with a 5 ppb concentration when I need to pump 2400 Gallons per minute total flow from both wells?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9784 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A equal the number of gallons pumped from well A in one minute to satisfy the conditions of the problem.\r<BR>\n" );
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document.write( "Let B equal the number of gallons pumped from well B in one minute to satisfy the conditions of the problem.\r<BR>\n" );
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document.write( "I need to pump 2400 Gallons per minute total flow from both wells.\r<BR>\n" );
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document.write( "A + B = gallons pumped from both wells in one minute, combining the first two conditions\r<BR>\n" );
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document.write( "A + B = 2400, combining all three conditions\r<BR>\n" );
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document.write( "change ppb to k / gal or kpg \r<BR>\n" );
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document.write( " A(18 kpg) + B(3 kpg) = 2400(5 kpg) \r<BR>\n" );
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document.write( " A(18 kpg) + (2400 - A)(3 kpg) = 12000 kpg\r<BR>\n" );
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document.write( "the units, kpg, all cancel  \r<BR>\n" );
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document.write( " 15A + 7200 -3A = 12000 \r<BR>\n" );
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document.write( " 12A = 4800 \r<BR>\n" );
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document.write( "A = 400 gal/min\r<BR>\n" );
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document.write( "B = 2000 gal/min\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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