document.write( "Question 20261: the sum of three consecutice numbers is 417. i ahve to write and solve an equation that will determine the three numbers. what are the three numbers? all i know is the numbers are in order and the equation looks something like x+y+z=471, but how do you figure that out? \n" ); document.write( "

Algebra.Com's Answer #9783 by elima(1433) $\"\"$ $\"About$

You can put this solution on YOUR website!
the sum of three consecutice numbers is 417.
\n" ); document.write( "You need 3 CONSECUTIVE numbers, 3 numbers that are one right after the other.
\n" ); document.write( "If you use x, y & z you are using 3 numbers that are not necessarily consecutive.
\n" ); document.write( "So we will begin by letting x be the first number, the next number will be the number right after x, so it will be x+1, and our third number will be two numbers after x, so it will be; x+2
\n" ); document.write( "so we have:
\n" ); document.write( "x+(x+1)+(x+2)=417
\n" ); document.write( "Now we can solve for x to get our first number.
\n" ); document.write( "Add al like terms first in the equation;
\n" ); document.write( "3x+3=417
\n" ); document.write( "Now subtract 3 from both sides;
\n" ); document.write( "3x+3-3=417-3
\n" ); document.write( "3x=414
\n" ); document.write( "Divide both sides by 3;
\n" ); document.write( " $\"3x%2F3\"$ = $\"414%2F3\"$
\n" ); document.write( "x=138
\n" ); document.write( "So now we have our first number;
\n" ); document.write( "So the second number would be;
\n" ); document.write( "x+1=138+1=139
\n" ); document.write( "So we have; 138,139
\n" ); document.write( "Now our third number would be;
\n" ); document.write( "x+2=138+2=140
\n" ); document.write( "So your three consecutive numbers are:
\n" ); document.write( "138, 139,140
\n" ); document.write( "Hope you understand
\n" ); document.write( "=) \n" ); document.write( "

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