document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133680>Question 133680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the position of a vertex for the graph of the function f(x) = x to the second power+6x+7\r<BR>\n" );
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document.write( "am desperate!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97826 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the vertex is on the axis of symmetry\r<BR>\n" );
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document.write( "for a quadratic of the form ax^2+bx+c, the equation for the axis is x=-b/2a\r<BR>\n" );
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document.write( "x=-6/2 or x=-3\r<BR>\n" );
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document.write( "to find the y-coordinate, substitute into the equation __ y=(-3)^2+6(-3)+7 __ y=-2\r<BR>\n" );
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document.write( "so the vertex is (-3,-2) </SPAN>\n" );
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