document.write( "Question 133686: How many lbs of Brazilian coffee costing $6.00 per lb must be mixed with how many lbs of columbian coffee costing $4.00 per lb to produce 36 lbs of a mixture costing $4.50 per lb? \n" ); document.write( "
Algebra.Com's Answer #97820 by stanbon(75887)\"\" \"About 
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How many lbs of Brazilian coffee costing $6.00 per lb must be mixed with how many lbs of columbian coffee costing $4.00 per lb to produce 36 lbs of a mixture costing $4.50 per lb?
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\n" ); document.write( "$6.00 coffee DATA:
\n" ); document.write( "Let amount be \"x\" lbs. ; Value is 6x dollars
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\n" ); document.write( "$4.00 Coffee DATA:
\n" ); document.write( "Amount is \"36-x\" lbs. ; Value is 4(35-x) = 140-4x dollars
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\n" ); document.write( "Mixture DATA:
\n" ); document.write( "Amount is 36 lbs : Value is 4.5(36) = 162 dollars
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\n" ); document.write( "EQUATION:
\n" ); document.write( "value + value = value
\n" ); document.write( "6x + 140-4x = 162
\n" ); document.write( "2x = 22
\n" ); document.write( "x = 11 lbs (Amount of $6 coffee in the mixtue)
\n" ); document.write( "36-11 = 25 lbs (Amount of $4.00 coffee in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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