document.write( "Question 133538This question is from textbook College algebra
\n" ); document.write( ": Let f(x)=x+1 and g(x)=6 /x+1 \r
\n" ); document.write( "\n" ); document.write( "Find (f*g)(1)\r
\n" ); document.write( "\n" ); document.write( "Here is what I have, but it seems to be incorrect. Can you please let me know where I've gone wrong?
\n" ); document.write( "f=1+1 and g=6/1+1
\n" ); document.write( "f=2 and g=6/2
\n" ); document.write( "f=2 and g=3
\n" ); document.write( "(2*3)=6\r
\n" ); document.write( "\n" ); document.write( "This is how I completed this one, but when I took my test, six was not the correct answer. Unfortunately, the correct answer is not given. I am curious to see what I did wrong.
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Algebra.Com's Answer #97797 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
I think the problem is aksing for (f(g(x)) at the value x =1.\r
\n" ); document.write( "\n" ); document.write( "What you need to do is take the function g(x) and use that as the independent variable in f(x). As follows:
\n" ); document.write( "\"f%28x%29+=+x%2B1\"
\n" ); document.write( "\"g%28x%29+=+6%2F%28x%2B1%29+\"\r
\n" ); document.write( "\n" ); document.write( "Now put the value of g(x) as the independent variable in f(x):
\n" ); document.write( "\"f%28g%28x%29%29+=+%286%2F%28x%2B1%29%29+%2B+1+\"
\n" ); document.write( "Now you can either solve for f(g(x)) and then sub in 1, or just sub in one and solve. Let's sub in 1:\r
\n" ); document.write( "\n" ); document.write( "\"f%28g%281%29%29+=+%286%2F%281%2B1%29%29+%2B+1+\"
\n" ); document.write( "\"f%28g%281%29%29+=+%286%2F2%29+%2B+1+\"
\n" ); document.write( "\"f%28g%281%29%29+=+3+%2B+1+\"
\n" ); document.write( "\"f%28g%28x%29%29+=+4+\"\r
\n" ); document.write( "\n" ); document.write( "For your info, generally the function f(g(x)) is written as (fog(x))\r
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