document.write( "Question 133637:
\n" ); document.write( "I am thinking of 3 consecutive positive numbers. If I multiply the first with the third and then add the second, the result is 41. What are the numbers?
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Algebra.Com's Answer #97788 by checkley71(8403)\"\" \"About 
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let x, x+1 & x+2 be the 3 consecutive numbers.
\n" ); document.write( "x(x+2)+(x+1)=41
\n" ); document.write( "x^2+2x+x+1=41
\n" ); document.write( "x^2+3x+1-41=0
\n" ); document.write( "x^2+3x-40=0
\n" ); document.write( "(x+8)(x-5)=0
\n" ); document.write( "x-5=0
\n" ); document.write( "x=5 answer for the smaller number
\n" ); document.write( "5+1=6 for the next number
\n" ); document.write( "5+2=7for the largest number
\n" ); document.write( "proof
\n" ); document.write( "5*7+6=41
\n" ); document.write( "35+6=41
\n" ); document.write( "41=41
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