document.write( "Question 133609: What is the answer to these systems of equations using addition to eliminate one of the variables?\r
\n" ); document.write( "\n" ); document.write( "4a-6b=15
\n" ); document.write( "6a-4b=10
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Algebra.Com's Answer #97771 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
4a-6b=15
\n" ); document.write( "6a-4b=10
\n" ); document.write( "-------------
\n" ); document.write( "Multiply 1st by 6 and multiply 2nd by 4 to get:\r
\n" ); document.write( "\n" ); document.write( "24a - 36b = 90
\n" ); document.write( "24a - 16b = 40
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\n" ); document.write( "subtract 1st from 2nd to get:
\n" ); document.write( "20b = -50
\n" ); document.write( "b = -5/2
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\n" ); document.write( "Substitute to solve for \"a\":
\n" ); document.write( "4(-5/2) -6b = 90
\n" ); document.write( "-10 -6b = 90
\n" ); document.write( "-6b = 100
\n" ); document.write( "b = -16.666667
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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