document.write( "Question 133599: Find a value for k that will make \"4x%5E2%2B12x%2Bk\" a perfect square. Describe the procedure that you used which requires algebra (this is not a trial and error). \n" ); document.write( "
Algebra.Com's Answer #97758 by solver91311(24713)\"\" \"About 
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Step 1: Divide the entire polynomial by the coefficient on the \"x%5E2\" term. \"x%5E2%2B3x%2Bk%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Divide the coefficient on the \"x\" term by 2: Result: \"3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Square the result of step 2: Result: \"9%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "The result of step 3 is the value of the constant term required to make \"x%5E2%2B3x%2Bk%2F4\" a perfect square, therefore \"k%2F4=9%2F4\" => \"k=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B9%2F4\" can be multiplied by 4 to reverse the effects of step 1, resulting in \"4x%5E2%2B12x%2B9\" which then factors to \"%282x%2B3%29%282x%2B3%29=%282x%2B3%29%5E2\"
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