document.write( "Question 133573: Paul and Susan are 725 miles apart and headed straight toward each other. If Paul is traveling at 75 mph and Susan is traveling at 70 mph, how many hours will it be before the two cars are side-by-side? \n" ); document.write( "
Algebra.Com's Answer #97730 by josmiceli(19441)\"\" \"About 
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The variable that is the same for both of them is time. If I
\n" ); document.write( "start my stopwatch when they are 725 mi apart and stop it
\n" ); document.write( "when they meet, they have both travelled for the same amount
\n" ); document.write( "of time.
\n" ); document.write( "Let \"d\" = distance that Paul travels
\n" ); document.write( "\"725+-+d\" will be the distance that Susan travels
\n" ); document.write( "For Paul:
\n" ); document.write( "\"t+=+d+%2F+75\" hrs
\n" ); document.write( "For Susan:
\n" ); document.write( "\"t+=+%28725+-+d%29+%2F+70\" hrs
\n" ); document.write( "Since their times are equal,
\n" ); document.write( "\"d%2F75+=+%28725+-+d%29+%2F+70\"
\n" ); document.write( "\"d%2F75+=+725%2F70+-+d%2F70\"
\n" ); document.write( "Multiply both sides by \"75%2A70\"
\n" ); document.write( "\"70d+=+75%2A725+-+75d\"
\n" ); document.write( "\"145d+=+54375\"
\n" ); document.write( "\"d+=+375\"
\n" ); document.write( "\"725+-+d+=+725+-+375\"
\n" ); document.write( "\"725+-+375+=+350\"
\n" ); document.write( "Now find \"t\"
\n" ); document.write( "\"t+=+d+%2F+75\"
\n" ); document.write( "\"t+=+375+%2F+75\"
\n" ); document.write( "\"t+=+5\" hrs
\n" ); document.write( "They will meet in 5 hrs
\n" ); document.write( "check:
\n" ); document.write( "\"d%2F75+=+%28725+-+d%29+%2F+70\"
\n" ); document.write( "\"375%2F75+=+350+%2F+70\"
\n" ); document.write( "\"5+=+5\"
\n" ); document.write( "OK
\n" ); document.write( "
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