document.write( "Question 133407This question is from textbook
\n" ); document.write( ": A car is driven 280 miles. If it had gone 5 mph faster, it could have made the trip in 1 hr less time. what was the speed? \n" ); document.write( "
Algebra.Com's Answer #97680 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "\"280+=+S+%2A+t+\"
\n" ); document.write( "\"+280%2FS+=+t+\"\r
\n" ); document.write( "\n" ); document.write( "If the car was drive 5 mph faster, it would have arrived 1 hour earlier. So
\n" ); document.write( "\"280+=+%28S%2B5%29+%2A+%28t-1%29\"
\n" ); document.write( "\"280+=+%28S%2B5%29+%2A+%28%28280%2FS%29+-1%29+\"
\n" ); document.write( "\"+280+=+%28S%2B5%29+%2A+%28%28280+-S%29%2FS%29+\"
\n" ); document.write( "\"+280+=+%28280+-+S%29+%2B+%285%28280+-S%29%29%2FS+\"
\n" ); document.write( "\"+0+=+-S+%2B+%281400+-5S%29%2FS+\"
\n" ); document.write( "\"+0+=+-S%5E2+-5S+%2B+1400+\"
\n" ); document.write( "\"+0+=+S%5E2+%2B+5S+-+1400+\"
\n" ); document.write( "\"+0+=+%28S+%2B+40%29+%28S++-+35%29+\"
\n" ); document.write( "S = -40 or S = 35. Since S can't be negative, S must be 35.\r
\n" ); document.write( "\n" ); document.write( "Check your answer.
\n" ); document.write( "280 / 35 = 8 hours
\n" ); document.write( "289 / 40 = 7 hours. Check!\r
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