document.write( "Question 133501: 2) $5000 is invested for 10 year compounds quarterly, at the end of the 10 years the amount as grown to $11,500. What is the annual interest percentage rate to the rounded to the nearest 100th?
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Algebra.Com's Answer #97672 by jim_thompson5910(35256)\"\" \"About 
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\"A=P%281%2Br%2Fn%29%5E%28nt%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"11500=5000%281%2Br%2F4%29%5E%284%2A10%29\" Plug in \"A=11500\", \"P=5000\", \"n=4\", and \"t=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"11500=5000%281%2Br%2F4%29%5E%2840%29\" Multiply \r
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\n" ); document.write( "\n" ); document.write( "\"2.3=1%2Br%2F4%29%5E%2840%29\" Divide both sides by 5,000 \r
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\n" ); document.write( "\n" ); document.write( "\"root%2840%2C2.3%29=root%2840%2C%281%2Br%2F4%29%5E%2840%29%29\" Take the 40th root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"1.02104=1%2Br%2F4\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"0.02104=r%2F4\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0.08416=r\" Multiply both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "\"r=0.08416\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "So to the nearest hundredth, the annual interest rate is 8.42%\r
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