document.write( "Question 133494: 1) How long will it take for $5000.00 to grow to $15,000.00 if the annual interest rate over that time is 4.85% and continuous compounding is used? \n" ); document.write( "
Algebra.Com's Answer #97670 by jim_thompson5910(35256)\"\" \"About 
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\"A=Pe%5E%28rt%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"15000=5000e%5E%280.0485t%29\" Plug in \"A=15000\", \"P=5000\", \"r=0.0485\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29=ln%285000e%5E%280.0485t%29%29\" Take the natural log of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29=ln%285000%29%2Bln%28e%5E%280.0485t%29%29\" Break up the natural log on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29-ln%285000%29=ln%28e%5E%280.0485t%29%29\" Subtract \"ln%285000%29\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29-ln%285000%29=0.0485t%2Aln%28e%29\" Rewrite the right side using the identity \"ln%28x%5Ey%29=y%2Aln%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29-ln%285000%29=0.0485t%2A1\" Evaluate \"ln%28e%29\" to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"ln%2815000%29-ln%285000%29=0.0485t\" Multiply \r
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\n" ); document.write( "\n" ); document.write( "\"%28ln%2815000%29-ln%285000%29%29%2F0.0485=t\" Divide both sides by 0.0485 to isolate t\r
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\n" ); document.write( "\n" ); document.write( "Using a calculator, we get\r
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\n" ); document.write( "\n" ); document.write( "\"t=22.6517998\"\r
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\n" ); document.write( "\n" ); document.write( "So it takes about 22.65 years for $5000.00 to grow to $15,000.00
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